Linear algebra · UNI_FOUNDATION

Determinants

Question 1/8+12 XP
Find .
Matrix as a transformationA = [0 3; 0 −2], det A = 0
-6-4-20246-4-224xy
area factor 0 — not invertible
original gridimage grid under Aimage of the unit square, area 0î ↦ (0, 0)ĵ ↦ (3, −2)
det A = 0: the two column vectors lie on one line. The unit square is flattened — the parallelogram degenerates to a segment with no area, and A is not invertible.